Question

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Answer 1

\large{\bf{\mathfrak{\dag{\blue{\underline{\underline{Answer}}}}}}}

$\frac{1 - \sin \: x}{ \cos \: x} = \frac{(1 - \sin \: x)(1 + \sin \: x )}{ (\cos \: x)(1 + \sin \: x ) }$

$= \frac{ {1}^{2} - { \sin }^{2} x }{(\cos \: x)(1 + \sin \: x )}$

$= \frac{ { \cos }^{2}x }{(\cos \: x)(1 + \sin \: x )}$

$= \frac{ \cos \: x}{1 + \sin \: x }$