Question

. solve it guys
50 points question

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Answer 1

Given,

x^p.y^q = (x+y)^(p+q)  

Taking log on both sides,

log x^p.y^q  = log (x+y)^(p+q)  

Diffrentiate w.r.t x:

log x^p + log y^q = (p +q ) log (x +y)

p log x + q log y = (p +q ) log (x +y)  

p / x + q /y . dy /dx = (p +q ) / (x +y) .[ 1 +  dy /dx]

[q / y - (p +q ) / (x +y) ] dy /dx = [(p +q ) / (x +y) - p / x]

[(qx + qy + -py - qy) / y (x + y)] . dy /dx = (px + qx - px - py) / x(x + y).

[(qx - py ) / y ] . dy /dx = (qx - py) / x

dy /dx = y / x

Answer 2

Explanation:

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