Question

.solve it guys.. fast​

Answer 1

SOLUTION :-

==> p(1,8)

==> x²+y²-6x-4y-11 = 0 -------(Given)

==> .°. x²+y²+2gx+2fy +c = 0

==> c' = (-g, -f)

==> .°. c = (3,2)

==> sum of opposite angle of cyclic quadrilateral =180°

==> Since, Quadrilateral 'PACB' is cyclic.

==> PC subtends right angle at point A.

==> PC is diameter of circle.

==> .°. p = (1,8) & C(3,2)

==> .°. c" = (x1+x2/2 , y1+y2/2) ----(by applying midpoint Formula)

==> .°. c" =(1+3/2 , 8+2/2)

==> .°. c" = (4/2 , 10/2)

==> .°. c" = (2,5)

==> .°. r = c"p

==> .°. r = √1+9

==> r = √10

==> .°. (x-2)² +(y-5)² = 10

==> .°. x² + y² - 4x-10y + 4 +25-10=0

==> .°. x²+y²-4x-10y+19=0.

Hence, The correct option is B.