solve it guys fast..... .....
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In BCE
BE^2 = BC^2 + CE^2
BE^2 = 5^2 + 12^2
BE^2 = 25 +144
BE^2 = 169
BE = Root 169
BE = 13
So, BE = AE = 13
AB = 24
Perimeter of triangle = BE+AE+AB
= 13+13+24
= 50
If you satisfied mark it brainliest.
BE^2 = BC^2 + CE^2
BE^2 = 5^2 + 12^2
BE^2 = 25 +144
BE^2 = 169
BE = Root 169
BE = 13
So, BE = AE = 13
AB = 24
Perimeter of triangle = BE+AE+AB
= 13+13+24
= 50
If you satisfied mark it brainliest.
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