Question

solve it guys ____pls refrain spamming....✌️​

Answer 1

Answer:

Question is from hc Verma!

when you integrate you will get sin-¹(x/a-1)

Therefore a raise n=1

so n=0

Answer 2

$\large\red{\underline{{\boxed{\textbf{Answer\:with\: Explanation}}}}}$

$\red{\bold{\underline{{ Left \: Hand\: Side\:LHS \: :}}}}$

$\large{\bold{\int \frac{dx}{ \sqrt{2ax - {x}^{2} }} }}$

${\bold{\frac{L}{ \sqrt{ {L}^{2} - {L}^{2} } }} }$

$\large {\bold{\frac{L}{ {L}^{2} }}}$ → ${\bold{\frac{L}{L} }}$ → $\large\red{\bold{{L}^{0} }}$

LHS is Dimensionless.

$\red{\bold{\underline{{ Right \: Hand\: Side\:RHS \: :}}}}$

${\bold {{a}^{n} {sin}^{-1} (\frac{x}{a} - 1)}}$ → ${\bold { {a}^{n} }}$

${L}^{n}$ → n = 0

RHS is also Dimensionless.

Explanation (Just For Understanding)

[ $\large{\bold {sin \: θ \: = \frac{4}{5}}}$ ]

θ = ${\bold { {sin}^{-1} (\frac{4}{5} )}}$

So the correct option is A 【$\red{0}$ 】✔️