Question

solve it guys
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Answer 1

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Question I referred to the .. questionar attachment....

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option (a)√11gl

$<font color=red><marquee behavior=alternate>Solution</marquee></font>$

now here given that ....

$\frac{(T1)max}{(T2)min} = \frac{2}{1}$

therefore....

$\frac{(T1)max}{(T2)min} = \frac{ \frac{m}{L} \times ((v1) {}^{2} + gL) }{ \frac{m}{L} \times ((v1) {}^{2} - 5gL) } \\ = > \frac{2}{1} = \frac{(v1) {}^{2} + gL}{(v1) {}^{2} - 5gL} \\ = > 2(v1) {}^{2} - 10gL = (v1) {}^{2} + gL \\ = > (v1) {}^{2} = 11gL\\ = > v1 = \sqrt{11gL}$

$<font color=green><marquee direction="Right">hope this help you$