solve it guyss fast.................
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PR>PQand PS bisects ∠QRP
TO PROVE ∠PSR>
∠PQR >∠PRQ (i) PR>PQ angle opposide to lear side is larger
∠QPS=∠RPS
(ii)(ps bisect ∠QPR)
∠PSR=PQR+∠QPS(iii)(exterior angle of a tranle equal to the sum of opposit interior angles )
∠PQR+∠QPS>∠PRQ+PRS
∠PSR>∠PSQ
I THINKE YAHI HO GA
TO PROVE ∠PSR>
∠PQR >∠PRQ (i) PR>PQ angle opposide to lear side is larger
∠QPS=∠RPS
(ii)(ps bisect ∠QPR)
∠PSR=PQR+∠QPS(iii)(exterior angle of a tranle equal to the sum of opposit interior angles )
∠PQR+∠QPS>∠PRQ+PRS
∠PSR>∠PSQ
I THINKE YAHI HO GA
perticasinghsoni:
good answer
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