Question

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Answer 1

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GIVEN

potential difference, ∆V = 1000 volts

velocity of proton , v = 4.37 × 10^5 m/s

mass of hockey ball , m = 0.1 kg

velocity of hockey ball = velocity of proton = 4.37 × 10^5 m/s

we have to find wavelength associated with hockey ball.

using De-broglie's wavelength equation,

wavelength = h/mv

= 6.63 × 10^-34 Js/(0.1kg × 4.37 × 10^5m/s)

= 6.63 × 10^-34/(0.437 × 10^5)

= 15.17 × 10^-39 m

= 1.517 × 10^-38 m

hence, answer is 1.517 × 10^-38 m

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Answer 2

Answer:

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Explanation:

potential difference, ∆V = 1000 volts

velocity of proton , v = 4.37 × 10^5 m/s

mass of hockey ball , m = 0.1 kg

velocity of hockey ball = velocity of proton = 4.37 × 10^5 m/s

we have to find wavelength associated with hockey ball.

using De-broglie's wavelength equation,

wavelength = h/mv

= 6.63 × 10^-34 Js/(0.1kg × 4.37 × 10^5m/s)

= 6.63 × 10^-34/(0.437 × 10^5)

= 15.17 × 10^-39 m

= 1.517 × 10^-38 m

hence, answer is 1.517 × 10^-38 m