Question

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Answer 1

Answer:

Given:

Volume of object = Vo

Density of object = do

Density of liquid = d

To find:

Fraction of object above the surface of the liquid.

Concept:

For floating object , the weight(mg) is balanced by the Buoyant force(Fb)

$\therefore \: mg = Fb$

$= > Vo \times do \times g = V \times d \times g$

$= > \frac{V}{Vo} = \frac{do}{d}$

Here V => volume of object inside the liquid.

So, V/Vo => fraction of volume of object inside the liquid.

Hence , fraction of volume outside the liquid is given as

$1 - \frac{V}{Vo}$

$= 1 - \frac{do}{d}$

$= \frac{d - do}{d}$

This is the fraction of volume of object outside the liquid.

$\boxed{ \boxed {final \: answer \: = option \: 3)}}$

Answer 2

Given:

Volume of object = Vo

Density of object = do

Density of liquid = d

To find:

Fraction of object above the surface of the liquid.

Concept:

For floating object , the weight(mg) is balanced by the Buoyant force(Fb)

\therefore \: mg = Fb∴mg=Fb

$= > Vo \times do \times g = V \times d \times g=>Vo×do×g=V×d×g</p><p>\begin{lgathered}= > \frac{V}{Vo} = \frac{do}{d} \\\end{lgathered}$=>VoV=ddo

Here V => volume of object inside the liquid.

So, V/Vo => fraction of volume of object inside the liquid.

Hence , fraction of volume outside the liquid is given as

$1 - \frac{V}{Vo}1−VoV</p><p>\begin{lgathered}= 1 - \frac{do}{d} \\\end{lgathered}=1−ddo</p><p>\begin{lgathered}= \frac{d - do}{d} \\\end{lgathered}=dd−do$

This is the fraction of volume of object outside the liquid.