Math, asked by Shivam901, 1 year ago

solve...it I need...it my exam is going to start from 11 am

Attachments:

Answers

Answered by siddhartharao77
3

Given, cos 2x cos(x/2) - cos 3x cos ( 9x/2)


On multiplying and dividing by 2  , we get


1/2 (2 cos 2x cos ( x/2) - 2 cos 3x cos ( 9x/2 ))


It is in the form of 2 cos x cos y = cos(x+y) + cos(x-y) 


= 1/2 (cos(2x + x/2 ) - cos(2x - x/2 ) - cos (3x + 9x / 2 ) + cos (3x - 9x/2 ))


= 1/2 (cos 5x/2 - cos 3x/2 - cos 15x/2 + cos3x/2)


= 1/2 (cos 5x/2 - cos 15x/2)


= 1/2 (-(- 2  sin 5x sin 5x/2 ))


= sin 5x sin 5x/2


Hope this helps!


Shivam901: check last three steps
siddhartharao77: What happened?
Shivam901: getting problem in last two steps how u write1/2 sin5x/2-sin15x/2 in -2sin5xsin5x/2
siddhartharao77: 1/2 (cos 5x/2 - cos 15x/2)

1/2 ( -(- 2 sin 5x sin 5x/2 ))

sin 5x sin 5x/2
Shivam901: cos5x/2-cos15x/2 is equal to sin5xsin5x/2 how
siddhartharao77: 1/2 (-(- 2 sin 5x sin 5x/2 ))

on cancelling 2 ,we get

(-(-sin 5x sin 5x/2)

= sin 5x sin 5x/2
siddhartharao77: There is one more solution to this problem :
= 1/2 (cos 5x/2 - cos 15x/2)

The formula is cos a- cos b= - 2 sin(a + b/2).sin(a-b/2)

= -2 sin 5x + 15x/4. sin 5x - 15x/4

= -sin 20x/4. -sin 10x/4

= sin 5x sin 5x/2
Answered by sparshsingh0506
0

Answer:

Cos sin =theta log in

Thanks

Similar questions