Question

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Answer 1

Step-by-step explanation:

$= > \frac{{ {3}^{5} }^{ \frac{n}{5} } \times {3}^{2n + 1}}{ {3}^{2n} \times {3}^{n - 1} } \\ = > \frac{ {3}^{n + 2n + 1} }{ {3}^{2n + n - 1} } \\ = > \frac{ {3}^{3n + 1} }{ {3}^{3n - 1} } \\ = > {3}^{3n + 1 - (3n - 1)} \\ = > {3}^{1 - ( - 1)} \\ = > {3}^{2} \\ = > 9$

Answer 2

Answer:

(243)^n/5 × 3^2n+1

9^n × 3^n-1

Step-by-step explanation:

(3⁵) ^ n/5 × 3 ^2n+1

(3²)^n ×3 ^ n-1

3^n × 3 ^2n+1

3^2n × 3^n-1

3^n+2n+1 => { a^b × a^c = a^b+c }

3^2n+n-1

: 3^3n + 1

3^3n-1

so,. 3^3n+1-(3n-1) => 3 ^ 3n+1-3n+1

hence, 3² = 9

Therefore 9 is the answer.

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