Question

solve it if you can and get 50 point
리
2
(a-3)² + (a+b-1) ²=
(2a-3)^2 + (a-3-1)^2
expand it ​​

Answer 1

$the \: answer \: is \: \boxed{{a}^{3} - {b}^{3} - 3ab(a - b) + {b}^{2} + 2ab = 4 {a}^{2} + 18 - 6a}$

Step-by-step explanation:

${(a - 3)}^{3} + {(a + b - 1)}^{2} = {(2a - 3)}^{2} + {(a - 3 - 1)}^{2}$

${a}^{3} - {b}^{3} - 3 {a}^{2} b \: +3a {b}^{2} + {a}^{2} + {b}^{2} + {1} + 2ab = \\ 4 {a}^{2} + 9 - 12a + {a}^{2} + 9 + 1 + 6a$

${a}^{3} - {b}^{3} - 3 {a}^{2} b+ 3ab^{2} + {a}^{2} + {b}^{2} + {1} + 2ab = 5 {a}^{2} + 19 - 6a$

${a}^{3} - {b}^{3} - 3ab(a - b) + {b}^{2} + 2ab = 4 {a}^{2} + 18 - 6a$

Answer 2

"(a-3)² + (a+b-1) ² = (2a-3)² + (a-3-1)²

"=> a² + 9 - 6a + a² + b² + 1 + 2ab -2b - 2a = 4a² + 9 - 12a + a² + 10 - 6a + 6 - 2a

"=> (a² + 9 - 6a - 2a) + a² + b² + 1 + 2ab -2b = (a² + 9 - 6a - 2a) + 4a² - 12a + 16

"=> a² + b² + 1 + 2ab -2b = 4a² - 12a + 16

"=> b² + 2ab -2b => 4a² - 12a + 16 - a² - 1

"=> b² + 2ab -2b => 3a² - 12a + 15

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