Question

solve it if you guys know of empirical formula​

Answer 1

hello dued please refer pic above

Answer 2

★ Answer :

The iron oxide has 69.9% iron and 30.1% dioxygen by mass.

Thus, 100 g of iron oxide contains 69.9 g iron and 30.1 g dioxygen.

The number of moles of iron present in 100 g of iron oxide are 69.9/55.8 =1.25

The number of moles of dioxygen present in 100 g of iron oxide are 30.1/32 = 0.94

The ratio of the number of oxygen atoms to the number of carbon atoms present in one formula unit of iron oxide is 2 × 0.94/1.25 = 1.5 : 1=3 : 2.

Hence, the formula of the iron oxide is Fe2O3.

$\rule{100}{2}$