Question

solve it in a copy with diagram.

Two ships leave a port at the same time one goes 24 km per hour in the direction North 45 degrees East and other Travels 32 km per hour in the direction South 75 degree east. find the distance between the ships at the end of 3 hours.

Answer 1

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Answer 2

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Here's your Answer....

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1st ship covers 24kmph for 3 hours = 24 × 3

=> 72 km.

Now,

Second ship covers 32kmph for 3 hours = 32 × 3

=> 96 km.

So, The 2nd Ship travels 96Km

∴∠AOB = 45° + (90°+ 75°)
= 60°

So, AB² = OA² + OB² - 2 × OA × OB × Cos60°

= 72² + 96² - 2 × 72 × 96 × 1/2 

=> AB = root 72^2 + 96^2 - 2 × 72 × 96 × 1/2 

=> AB =86.53 km.
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