solve it: in a triangle ABC. AB=BC, ANGLE B=x and angle A=2x-20 degee. find angle b(with solution)
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In triangle ABC, AB = BC. Therefore, angle B = angle C = x.
Also given , angle A = 2x - 20.
By angle sum property of a triangle,
we have angle A + angle B + angle C = 180 degrees
so , 2x - 20 + x + x = 180
=> 4x = 180 + 20
=> 4x = 200
=> x = 50 degrees
Therefore, angle B = 50 degrees. (angle A = 2(50) - 20 = 80 degrees and angle C = 50 degrees)
Also given , angle A = 2x - 20.
By angle sum property of a triangle,
we have angle A + angle B + angle C = 180 degrees
so , 2x - 20 + x + x = 180
=> 4x = 180 + 20
=> 4x = 200
=> x = 50 degrees
Therefore, angle B = 50 degrees. (angle A = 2(50) - 20 = 80 degrees and angle C = 50 degrees)
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