Math, asked by mantuchand1579, 1 year ago

solve it in simple way

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Answered by Anonymous
1
√p.p+ q.q= q sec theta

RHS

q sec + q)/ q sec - q

sec+ 1/ sec -1

( sec + 1)^2/ tan^2

LHS

q sec /p + q/p)^2

q( 1 + sec)/p)^2

q^2 ( 1 + sec)^2/p^2

AS √ p^2 + q^2 = q sec

p^2 + q^2 = q^2 sec^2

(p/q)^2 + 1 = sec^2

( p/q)^2 = sec^2 -1

substitute in q^2( 1+ sec)^2/ p^2

(sec +1)^2/ sec^2 -1

sec+1)^2/ tan^2 = RHS
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