solve it ...it's from ncert class 10 book....ch 8 trigonometry ex 8.2
Answers
Answer:
5 ( √3/2)² + 4 (2)² - (1/√2)²
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(1/2)² + (√3/2)²
=> 5√3/4 + 16 - 1/2
________________
√3+1/4
=> 5√3-2/4 + 64/4
__________________
√3+1/4
cancelled out 4
5√3+62
_______ Ans.
√3+1
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5 cos²60°+4sec²30°-tan²45°
_______________________
sin²30°+cos²30°
= 5×(1/2)²+4×(2/√3)²-1²
________________
(1/2)²+(√3/2)²
= 5×1/4+4×4/3-1
___________
1/4+3/4
= 5×1/4+4×4/3-1
____________
1+3
____
4
= 5×1/4+4×4/3-1
___________
1
= 5/4+16/3-1
= 15+64-12
_______
12
= 79-12
____
12
= 67
__
12