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(6y+7)/(3y+2)=(4y+5)/(2y+3)
By cross multiplication we get,
(6y+7)(2y+3)=(4y+5)(3y+2)
=>12y^2+18y+14y+21=12y^2+8y+15y+10
Cancelling 12y^2 on both sides we get,
32y+21=23y+10
=>9y=-11
=>y=-11/9
By cross multiplication we get,
(6y+7)(2y+3)=(4y+5)(3y+2)
=>12y^2+18y+14y+21=12y^2+8y+15y+10
Cancelling 12y^2 on both sides we get,
32y+21=23y+10
=>9y=-11
=>y=-11/9
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Answer:
-11/9
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