solve it - Maggie 6 year older than her sister shaily. in the sum of their ages is 16year. what are their present ages?
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let the age of Shaily = x
let the age of Maggie = x+6
Now ,
x+x+6 = 16
2x + 6 = 16
2x = 16 - 6
2x = 10
x = 10 ÷2
x = 5 (ans)
Then , Age of Shaily = (x) 5 years old
Age of Maggie= x+6
= 5+ 6
= 11 years old (Ans)
In extra ,, ❤
Check = L.H.S. = R.H.S.
L.H.S. = (we put the value of X in L.H.S.)
x+x+6
5+5+6
10+6
16 (Ans)
L.H.S. = 16
R.H.S. = 16
Hence , L.H.S. = R.H.S.
Proved ✅
Hope it helps you buddy ....✌
If you are satisfied with this answer please mark me as brainliest ❤
let the age of Maggie = x+6
Now ,
x+x+6 = 16
2x + 6 = 16
2x = 16 - 6
2x = 10
x = 10 ÷2
x = 5 (ans)
Then , Age of Shaily = (x) 5 years old
Age of Maggie= x+6
= 5+ 6
= 11 years old (Ans)
In extra ,, ❤
Check = L.H.S. = R.H.S.
L.H.S. = (we put the value of X in L.H.S.)
x+x+6
5+5+6
10+6
16 (Ans)
L.H.S. = 16
R.H.S. = 16
Hence , L.H.S. = R.H.S.
Proved ✅
Hope it helps you buddy ....✌
If you are satisfied with this answer please mark me as brainliest ❤
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I believe this is the answer
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