Question

solve it mates...........

Answer 1

hello mate......!!!!


》 given.......


$log( \frac{x + y}{5} ) = \frac{1}{2} (logx + logy) \\ \\we \: know \: .... \\ log(x y )= logx + logy\\ \\ log( \frac{x + y}{5} ) = \frac{1}{2} (logx y) \\ \\ log( \frac{x + y}{5} ) = log(xy) {}^{ \frac{1}{2} } \\ \\ then...log \: will \: be \: remove \: both \: sides... \\ \\ ( \frac{x + y}{5} )=( xy) {}^{ \frac{1}{2} } \\ \\ apply \: both \: side \: squre... \\ \\ ( \frac{x + y}{5} ) {}^{2} = xy \\ \\ (x + y) {}^{2} = 25xy \\ \\ x {}^{2} + y {}^{2} + 2xy = 25xy \\ \\ x { }^{2} + y {}^{2} = 23xy \\ \\ \\hence \: proved \: ur \: condtion.... \\ \\ hope \: it \: helps \: u \: dear.....$