Math, asked by kachangthaipou, 1 year ago

solve it ....maths cbse

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Answered by Anonymous

Hey dear!!

Here is yr answer.....

x-3/x-4 + x-5/x-6 = 10/3

3[(x-3)(x-6)+(x-4)(x-5)] = 10(x²-10x+24)

3 (2x2-18x-38) = 10x²-100x+240

6x²-54x-114 = 10x²-100x+240

10x²-6x²-100x+54x+240-114 = 0

4x²-46x+126 = 0

2x²-23x+63 = 0

2x²-14x-9x+63 = 0

2x(x-7) -9(x-7) = 0

(x-7)(2x-9) = 0

Therefore ,

x = 7

x = 9/2

Hope it hlpz....

Anonymous: I don't know correct ans

Anonymous: I tried to answer

siddhartharao77: 9/2,7

Anonymous: I just completed 9th

Akanksha1710: wait is my answers correct??

siddhartharao77: There is a little mistake in steps..thats it

Anonymous: corrected bro

Anonymous: tq

siddhartharao77: Good

Anonymous: tq

Answered by Akanksha1710

(x-3)(x-6)+(x-5)(x-4)
_ _ _ _ _ _ _ _ _ =10/3
(x-4)(x-6)

x²-9x+18+x²-9x+20
_ _ _ _ _ _ _ _ _ _ _ =10/3
x²-10x+24

3(2x²-18x+38)=10(x²-10x+24)
6x²-54x+114 = 10x²-100x+240
4x²-46x+126=0( take 2as common)
2x²-23x+63=0
2x²-14x-9x+63=0
(2x-9)(x-7)=
value of x will be x=7 or x=9/2
HOPE THIS WILL HELP U FRIEND

Akanksha1710: ,pls mark as brainiest

Akanksha1710: ok ...

siddhartharao77: The answer is 9/2,7

Akanksha1710: now it is correct

Akanksha1710: pls do mark as brainliest

siddhartharao77: I didn't asked the question

kachangthaipou: sidhart ...stfu

Akanksha1710: i know that whosoever asked...can mark it

siddhartharao77: What do u mean by stfu @kachang

Akanksha1710: pls do mark it as the brainliest

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