Question

solve it no spam..... ok

Answer 1

$\bold{Answer :}$

Ranjan and Rohit had coins in the ratio 11:7

Let, the common multiple be x

Then, Ranjan had 11x coins and Rohit had 7x coins

By the given condition,

11x + 7x = 468

or, 18x = 468

or, x = 468/18

or, x = 26

So, Ranjan had (11 × 26) = 286 coins

and Rohit had (7 × 26) = 182 coins

Ranjan's mother gave him 14 more coins; so he has (286 + 14) = 300 coins now

Let us take Rohit's mother took y number of coins from him; so he has (182 - y) coins now

By the given condition,

300 : (182 - y) = 15 : 8

or, 300/(182 - y) = 15/8

or, 15 (182 - y) = 300 × 8

or, 182 - y = (300/15) × 8

or, 182 - y = 20 × 8 = 160

Therefore, Rohit has 160 coins now.

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