Math, asked by yoyoyo79, 10 months ago

solve it no wrong ans plz

Attachments:

Answers

Answered by Anonymous

Answer:

$<body bgcolor=pink><marquee direction="up"><font color=purple>$

Now, l + b + h = 19 CM.

Given it's diagonal = 5√5 cm.

Diagonal = √ l² + b² + h² = 5√5

125 = l² + b² + h²

Also, T. S. A = 2(lb+bh+hl)

Now, Take l + b + h = 19

Squaring on both sides

(l + b + h) ² = 19²

l² + b ² + h² + 2 ( lb+ bh+hl) = 361

125 + TSA = 361

TSA = 236 cm²

Therefore, T. S. A = 236 cm²

$<body bgcolor=pink><marquee direction="down"><font color=black>$

30thx On Math Answers +Follow =INBOX

♥Follow meeee♥

Answered by Anonymous

Answer:

$\boxed{\sf Surface \ area \ of \ cuboid =236 \: {cm}^{2}}$

Given:

Sum of the length, breadth and depth of a cuboid = 19 cm

Diagonal of cuboid = 5 $\sf \sqrt{5}$ cm

To find:

Surface area of cuboid

Step-by-step explanation:

Let,

Length = l

Breadth = b

Depth = d

So,

$\sf \implies l + b + d = 19$

$\sf Diagonal \ of \ cuboid = \sqrt{l^{2} + b^{2} + d^{2}} \\ \\ \sf \implies 5 \sqrt{5} = \sqrt{ {l}^{2} + {b}^{2} + {d}^{2} } \\ \\ \sf \implies {(5 \sqrt{5} )}^{2} = {l}^{2} + {b}^{2} + {d}^{2} \\ \\ \sf \implies {l}^{2} + {b}^{2} + {d}^{2} = 25 \times 5\\ \\ \sf \implies {l}^{2} + {b}^{2} + {d}^{2} = 125 \: cm$

$\sf Surface \ area \ of \ cuboid = 2(lb + bd + ld)$

As we know,

$\sf (l + b + d)^{2} = {l}^{2} + {b}^{2} + {d}^{2} + 2(lb + bd + ld)$

By substituting respective values of (l + b + d) and (l² + b² + d²) in the above formula we can find surface area of cuboid

$\sf \implies \sf (l + b + d)^{2} = ( {l}^{2} + {b}^{2} + {d}^{2} )+ 2(lb + bd + ld) \\ \\ \sf \implies {(19)}^{2} = (125) + 2(lb + bd + ld) \\ \\ \sf \implies 361 = 125 + 2(lb + bd + ld) \\ \\ \sf \implies 361 - 125 = 2(lb + bd + ld) \\ \\ \sf \implies 236 = 2(lb + bd + ld) \\ \\ \sf \implies 2(lb + bd + ld) = 236 \: {cm}^{2} \\ \\ \sf \implies Surface \ area \ of \ cuboid =236 \: {cm}^{2}$

Previous Question

Next Question

solve it no wrong ans plz ​

Answers

solve it no wrong ans plz