Math, asked by shubhamjii, 10 months ago

solve it now.......

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Answers

Answered by navneet145
0

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Answered by Anonymous
16

SOLUTION

x^2 + x -p(p+1)=0

Here it's in the form of

 {ax}^{2}   + bx + c = 0

Therefore,

a= 1

b= 1

c= -p^2 -p

D =  {b}^{2}  - 4ac

=) 1-4×1 ×(-p^2-p)

=) 1+ 4p^2 +4p

Now, alpha= -b+D/2a

=) -1+ 2p +1/2

=) 2p/2= p

& beta = -b + D/2a

=) -1-2p-1/2

=) -2-2p/2

=) -2(1+p)/2

=) -1-p

Therefore, the roots are (-p) & (-1-p)

hope it helps ☺️

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