Question

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Answer 1

Step-by-step explanation:

hey friend

here is ur answer:

The length of park= 30 m

The breadth of the park= 25m

The length of outer rectangle(path and park)=30+1.5+1.5=33m

The breadth of outer rectangle=25+1.5+1.5=28m

The perimeter of the fence=2(30+25)=2*65m=130m

THe area of outer rectangle=33m * 28m=924 m2

the area of the park= 25m * 30m= 750m2

The area of the path= 924-750

174 m2

Hope this will help you...Plz mark it as BRAINLEST...

Answer 2

Step-by-step explanation:

length of park =30m

breadth of park = 25m

perimeter of fence=2(l+b)

• = 2(30 + 25)m
• = 2 × 55m = 110m

area of path = area of parking along the footpath - area of park

area of path along footpath= l×b

= (1.5 + 30 + 1.5)m × (1.5 + 25 + 1.5)m

= 33 × 28 = 924m^2

area of park = l×b

= 30 × 25 = 750m^2

so, area of footpath = (924 - 750)m^2

• = 174m^2

hope it helps you...

plzzz mark it as brainliest...