Question

Solve it on a graph 4x-3y+4=0, 4x+3y-24=0.​

Answer 1

Given:

A set of equations 4x-3y+4=0, 4x+3y-24=0.​

To find:

Solve it on a graph 4x - 3y + 4 = 0, 4x + 3y - 24 = 0.​

Solution:

From given, we have,

A set of equations 4x - 3y + 4 = 0, 4x + 3y - 24 = 0

Consider the attached figure for the graph of 4x - 3y + 4 = 0, 4x + 3y - 24 = 0

From the figure it's clear that, the lines of these equations intersect at point (5/2, 14/3).

Verfication:

4x - 3y + 4 = 0, 4x + 3y - 24 = 0

adding both the equations, we get,

8x - 20 = 0

x = 20/8

x = 5/2

sbstituting the value of x in one of the equations, we get,

4(5/2) + 3y - 24 = 0

10 + 3y - 24 = 0

3y - 14 = 0

y = 14/3

Answer 2

Answer:

This is the answer.

Step-by-step explanation:

(0,8) (2.5,4.6) (0,1.3)