solve it on rough page
i will mark it as brainliest
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here is the explanation
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ravindervirk360:
6-x-x^2
give answer
is it a quadratic equation?
like 6-x-x^2=0
like 6-x-x^2
the question is confusing, if it is a quadratic equation, 6-x-x^2 =0 => x^2+x-6=0=>x^2+3x-2x-6=0=>. x(x+3)-2(x+3)=0. =>(x+3)(x-2)=0. =>x= -3, x= 2
(root 3/root 5)^x+1=125/27 , find x
Answered by
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Hello there!
Let the number to be subtracted be 'x'
As per the condition given, the equation will be: (-5/3) - x = (5/6)
Calculation:
(-5/3) - x = (5/6)
-x = (5/6)-(-5/3)
-x = (5/6)+(5/3)
LCM for 6,3 is 6
-x = (5+5(2))/6
-x = (10+5)/6
-x = 15/6
both 15 and 6 are the multiples of 3 for 5 and 2
-x = 5/2
x = -5/2
Therefore, the number to be subtracted from (-5/3) to get (5/6) is (-5/2)
Let the number to be subtracted be 'x'
As per the condition given, the equation will be: (-5/3) - x = (5/6)
Calculation:
(-5/3) - x = (5/6)
-x = (5/6)-(-5/3)
-x = (5/6)+(5/3)
LCM for 6,3 is 6
-x = (5+5(2))/6
-x = (10+5)/6
-x = 15/6
both 15 and 6 are the multiples of 3 for 5 and 2
-x = 5/2
x = -5/2
Therefore, the number to be subtracted from (-5/3) to get (5/6) is (-5/2)
using factor show m-n,n-p,p-m are factor of m(n^2-p^2)+n(p^2-m^2)+p(m^2-n^2)
give amswer
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