Solve it on the basis of triangle
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Given:
BL = CM
To prove:
AD is median of Δ ABC.
Proof:
In Δ BLD and Δ CMD,
BL = CM ... [ given ]
∠ BLD = ∠ CMD ... [ each is 90° ]
∠ BDL = ∠ CDM ... [ vertically opposite angles are equal ]
Therefore, Δ BLD ≅ Δ CMD by AAS test.
Thus BD = CD
This implies that, D divides BC in two equal parts.
Therefore, BD is median of Δ ABC.
Hence, proved.
Hope it helps!!!
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Answer:
provided with three test tubes. One of them contains distilled water and the other two have an acidic solution and a basic solution respectively. If you are given only red litmus paper, how will you identify the contents of each test tube? 6. HCI, HNO, C,H,OH
Step-by-step explanation:
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