solve it or prove it question
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Hey !!!
from LHS
=cosA √1 + cot²A
=cosA × √cosec²A ✔•°• cosec²A = 1 + cot²A
=cosA × cosecA
= cosA×1/sinA = cosA/sinA
=cotA
From RHS
√cosec²A - 1
we know that , cosec²A - 1 = cot²A
hence, √cosec²A - 1 = √cot²A
= cotA
So, LHS = RHS prooved here
_____________________________
Hope it helps you !!!
@Rajukumar111
from LHS
=cosA √1 + cot²A
=cosA × √cosec²A ✔•°• cosec²A = 1 + cot²A
=cosA × cosecA
= cosA×1/sinA = cosA/sinA
=cotA
From RHS
√cosec²A - 1
we know that , cosec²A - 1 = cot²A
hence, √cosec²A - 1 = √cot²A
= cotA
So, LHS = RHS prooved here
_____________________________
Hope it helps you !!!
@Rajukumar111
raj1132:
I don,t understand
Answered by
0
LHS:
cos A (1+cot^2A)^1/2
cos A (1+cos^2A/sin^2A)^1/2
cos A/sinA (sin^2A+cos^2A)^1/2
cot A (1)^1/2
cot A
now, taking both lhs and rhs
cot A= (cosec^2-1)^1/2
squaring both side
cot^2A=(cosec^2-1)
hence proved...
hope it will help you.
cos A (1+cot^2A)^1/2
cos A (1+cos^2A/sin^2A)^1/2
cos A/sinA (sin^2A+cos^2A)^1/2
cot A (1)^1/2
cot A
now, taking both lhs and rhs
cot A= (cosec^2-1)^1/2
squaring both side
cot^2A=(cosec^2-1)
hence proved...
hope it will help you.
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