solve it out its urjnt guyz can any one help me out
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We have a square ABCD
BD is a diagonal
Hence angle DBC is is 45°
Since angle EBC is 60° (angle of equilateral triangle)
angle EBO = angle EBC-angle DBC
i.e angle EBO=15°
by exterior angle property
angle x = angle EBO + angle BEO
i.e x = 15+60
= 75°
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