Question

solve it
P(-3,7),Q(1,-4),a:b=2:1​

Answer 1

Answer:

Given,  

Co-ordinates of the Point P (x₁, y₁) = (-3,7)  

Co-ordinates of the Point Q (x₂, y₂) = (1,-4)

Ration of division ( m₁:m₂) = 2 : 1

Now, Using the Section Formula,  

A(x,y) = [(m₁x₂ + m₂x₁)/(m₁ + m₂) , (m₁y₂ + m₂y₁)/(m₁ + m₂)]

          = [( 2 × 1 +  1 × -3 )/(2 + 1) , (2 × -4  +  1 × 7  )/(2 + 1)]          

         = [-1/3 , -1/3]

         = (-1/3,-1/3)  

Hence, the co-ordinates of the Point A is (-1/3,-1/3).

Hope it helps...