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The height of the building is 19.6 m. When the ball hits the ground, it makes the angle of 45 degrees.
Then the initial velocity of the ball is calculated below.
It is a known fact that T = (2h/g)
T = (2 x 19.6 m/(9.8 m/s2))
The value of T is 2 s.
U = 19.6/2
The value of U is 9.8 m/s^2
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