Question

solve it plddd☺writting handle kr lena❣sholly​

Answer 1

Step-by-step explanation:

$\bold{x = 2a}$

$\bold{y = 4b}$

$\bold{(i) \: \: (x + y)^{2} }$

$\large {\underline{ \pink{ \bold{Formula :-}}}}$

$\bold{(x + y)^{2} = {x}^{2} + 2xy + {y}^{2} }$

$\bold{x = 2a \: \: , \: \: y = 4b}$

$\bold{(2a + 4b)^{2} = {(2a)}^{2} + 2(2a)(4b) + (4b)^{2} }$

$\bold { = 4 {a}^{2} + 16ab + 16 {b}^{2} }$

$\bold{(ii) \: \: (x - y)^{2} }$

$\large {\underline{ \pink{ \bold{Formula :-}}}}$

$\bold{(x - y)^{2} = {x}^{2} - 2xy + {y}^{2} }$

$\bold{x = 2a \: \: , \: \: y = 4b}$

$\bold{(2a - 4b)^{2} = {(2a)}^{2} - 2(2a)(4b) + (4b)^{2} }$

$\bold { = 4 {a}^{2} - 16ab + 16 {b}^{2} }$

$\bold{(iii) \: \: (x + y)^{3} }$

$\large {\underline{ \pink{ \bold{Formula :-}}}}$

$\bold{(x + y)^{3} = x^{3} + 3x ^{2} y + 3x {y}^{2} + {y}^{3} }$

$\bold{x = 2a \: \: , \: \: y = 4b}$

$\bold{ \scriptsize{(2a + 4b)^{3} = {(2a)}^{3} + 3(2a)^{2} (4b) + 3(2a) {(4b)}^{2} (4b)^{3} }}$

$\bold{ \scriptsize{ = 8 {a}^{3} + 48 {a}^{2}b + 96a {b}^{2} + 16 {a}^{3} }}$

I hope it is helpful

Answer 2

Answer:

hlo bhai aap kaise ho

mai theek hu aur aap bhi ache se rehne aapke questions me space nhi tha isliye no reply

have a nice day ahead