Math, asked by RealPoet, 11 months ago

Solve It please !!!!!!!!!!​

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Answered by Anonymous
3

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=>(y-1)/(y+1)=(2y-3)/(2y+3)

=>(y-1)(2y+3)=(y+1)(2y-3)

=>2y²+y-3=2y²-y-3

=>y+y=0

=>y=0

\underline{\large\mathcal\red{hope\: this \: helps \:you......}}

Answered by divya306281
2

y+1/y-1=2y+3/2y-3

y=0/2

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