Solve It please !!!!!!!!!!
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=>(y-1)/(y+1)=(2y-3)/(2y+3)
=>(y-1)(2y+3)=(y+1)(2y-3)
=>2y²+y-3=2y²-y-3
=>y+y=0
=>y=0
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2
y+1/y-1=2y+3/2y-3
y=0/2
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