Question

solve it please 15,16,17,18,19,20

Answer 1

20,19,18,17,16,15 is it right

Answer 2

Answer:

Step-by-step explanation:

15.

radius of the park = 84/2 = 42m

area of the park = (22/7)×42×42 = 5544m^2

width of road = 3.5m

.•.total radius = 3.5+42 = 45.5m

total area = (22/7)×45.5×45.5 = 6506.5m^2

area cover by the road=6506.5-5544= 1062.5m^2

total cost of constructing the road=1062.5×240=Rs255000

16.

Let R be the radius of the Outer circular path ..

and the Circumference of outer circular path is given 44m ..

2∏R = 44

∏R = 22

R = 7 m ..

Now width = 2m .

Inner radius (r) = 7 - 2 r = 5 m ..

Inner circumference

2πr

2 × 22/7 × 5

220/7

31.42 m

Area of path ..

Outer area of circular path - inner Area ..

∏R² - ∏r²

∏(7)² - ∏(5)²

75.43 m^2

17.

Area =  \pi  (R²-r²)

770 = 22/7 × [(21)² - r²]

770×7÷22 = 441-r²

441 - 245 = r²

r² = 196

r = √196

r = 14cm

18.

r=14 cm

total area= πr²

=22/7*196=616 cm²

r2= 3.5 cm

area of the small circles= 2*πr²=2*12.25*22/7=77 cm²

length of rectangle=3

breadth=1

area =lb=3 cm²

area of the small circles+area of rectangle=77+3=80 cm²

remaining area=616-80=536 cm²

19.

(i)area of the shaded region= area of rectangle- area of semicircle

l*b - 1/2*pi r^2

7*10 - 1/2*22/7* 7/2*7/2

70 - 19.25

= 50.75cm^2

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