Question

solve it please ...............

Answer 1

the answer is probably y=x because it is uniform acceleration

Answer 2

Starting Velocity (u) = 0

Time (t) = 3 secs.
If, Acceleration = a

Then,

Distance, X = ut + (at^2)/2

X = 0 + a×3^2/2

X = 9a / 2 metres.....●

Now, after 3 seconds the starting velocity will,

v = u + at

v = 0 + a×3

v = 3a

Now, this velocity will work as Starting Velocity for next three seconds travel,

Thus,

Distance, Y = ut + (at^2)/2

Y = 3a×3 + a×3^2/2

Y = 9a + 9a/2

Y = 27a / 2.....●

Now, if we compare X and Y =>

X = 9a/2 ..... Y = 27a/2

If we multiply X by 3........

3X = 9×3a / 2

3X = 27a / 2 = Y

Thus, Y = 3X........●

Option "B" is correct.

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Hope it was helpful.