Question

Solve it please agar aatta ton hi kare​

Answer 1

Answer:

refer to pic above please

Answer 2

$<font color="green">$★FIND:

$\bold{Derivative \:of \:f(x)=sinx^2}$

★GIVEN:

➡️$\bold{f(x)=sinx^2}$

★SOLUTION:

$\bold{f'(x) = \cos(x {}^{2} ) \frac{d(x{}^{2}) }{dx}}$

$\bold{f'(x) = \cos(x {}^{2} ) (2x) \frac{d(x)}{dx}}$

$\bold{f'(x) = \cos(x {}^{2} ) (2x)(1)}$

$\bold{f'(x) = 2x( \cos( {x}^{2} ))}$