Math, asked by virat293, 10 months ago

solve it please all q 50 pts​

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Answered by Anonymous
5

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The 7th term is a + 6d = -39/12

The 15th term is a + 14d = -103/12

Equating these terms with their values and solving as simultaneous equations, we get a = 3/4 and d = – 2/3.So the 27th term is (a + 26d) = 3/4 + (-52/3) = -199/12

The AP can be expressed as a, (a + d), ---, (a +20d). The sum of the first 3 terms is (3a + 3d) = -33 and the sum of the middle 3 terms is (3a + 30d) = 75. Solving these two equations, we get a = -15 and d = 4. The sum of the 1st 21 terms is (21/2) (2 * -15 + 20 * 4) = 525.

The 6th term is a + 5d = 6

The 16th term is a + 15d = 14

Equating these terms with their values and solving as simultaneous equations, we get a = 2 and d = 4/5. So the 27th term is (a + 26d) = 2 + (104/5) = 114/5.

Answered by aadishree7667
4

✌hope it helps you......

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