Math, asked by kanti19821982, 9 months ago

solve it please also explain it ​

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Answered by Anonymous
1

Answer:

i) =  {( \frac{3}{4}) }^{2}  \times  { ( - \frac{3}{4}) }^{3}  \\  \\  =  - ( { \frac{3}{4} )}^{2 + 3}  \\  \\  =  -   {(\frac{3}{4} )}^{5}  \\  \\ ii) \\  =  {( \frac{4}{7}) }^{3}  \times  {( \frac{4}{7}) }^{5}  \\  \\  =  {( \frac{4}{7} )}^{3 + 5}  \\  \\  =  { (\frac{4}{7}) }^{8}

Answered by Anonymous
1

Answer:

Step-by-step explanation:

(1)

(3/4)³x(-3/4)³=-(3/4)^5

27/64 x 27/64 =-(3/4)^5

729/4096 =243/1024

hence they are not equal

we can easily say that second statement is true

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