Question

solve it please!! don't spam

Answer 1

Given :-

• AB = 12 cm
• OP = 8 cm

To find :-

• Radius of the circle

According to the question,

• By using Pythagoras theorem,

$\sf : \implies{OB {}^{2} = OP {}^{2} + PB {}^{2} }$

$\sf : \implies{OB {}^{2} = {(8 \: cm)}^{2} + {(6 \: cm)}^{2} }$

$\sf : \implies{OB { }^{2} = 64 \: {cm}^{2} + 36 \: {cm}^{2} }$

$\sf: \implies{OB {}^{2} = {100 \: cm}^{2} }$

$\sf: \implies{OB = \sqrt{100 \: cm {}^{2} } }$

${ \underline{ \boxed{\sf { \pink{ : \implies{OB = 10 \: cm}}}}}} \: \bigstar$

$\therefore{ \underline{ \sf{So, the \: radius \: of \: the \: circle \: is { \textsf{ \textbf{10 cm.}}}}}}$

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Theorem 1 :-

• The angle subtended by an arc of a circle at the centre is doubled the angle subtended by it at any point on the remaining part of the circle.

Theorem 2 :-

• The angle in a semicircle is a right angle.

Theorem 3 :-

• Angles in the same segment of a circle are equal.

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Answer 2

Answer:

10cm

Explanation:

Here's the required answer