Question

Solve it please....faaaaaaaassst..

A 10 CM long stick is kept in front of a concave mirror having focal length of 10cm in such a way that the end of the stick closest to the pole is at a distance of 20cm. What will be the length of the image.

Answer 1

Hello friend
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=) Given:

Object size(h1) = 10cm.

object distance (u) = -20cm.

focal length= 10cm

To find: Image size (h2) = ??

Therefore,

1/v + 1/u = 1/f

M = h2/h1 = V/u

: 1/v + 1/u = 1/f

: 1/v + 1/-20 = 1/-10

: 1/v = 1/-10 + 1/20

: 1/v = ( -2+1)/20

: 1/v = -1/20

: v = -20cm.


Now,

M = h2/h1 = - V/u

= h2/h1 = - v/u

: h2 = -(v * h1)/u

: h2 = -(-20*10)/-20

: h2 = -10cm.

Therefore the height of the image means the length is 10cm and it is a real and inverted image.

I hope this will helps you.

Thanks.