Question

solve it please for some reason

Answer 1

let greater angle be x
x+x=180*(by ASPT)
2x=180*
x=180*÷2
x=90*

Answer 2

Given ΔABC, extend BA to D such that
AD = AC.
Now in ΔDBC
∠ADC = ∠ACD [Angles opposite to equal sides are equal]
Hence ∠BCD > ∠ BDC
That is BD > BC [The side opposite to the larger (greater) angle is longer]
Þ AB + AD > BC 
∴ AB + AC > BC [Since AD = AC)
Thus sum of two sides of a triangle is always greater than third side.