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it is a theorem of circles...
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ritesh058198:
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Answer:
Step-by-step explanation:
Given: Seg AC and BC are tangents
To Prove: CA= CB
Construction: Seg CO and Radius OB and OA
Solution: In Δ AOC and Δ BOC
Seg CO ≅ Seg CO _______(Construction)____(Common Side)
∠OAC ≅ ∠OBC __________( Tangent Theorem)
Seg AO ≅ Seg BO _______(Radii Of Same Circle)
∴ Δ AOC ≅ ΔBOC __________(By S-A-S Test Of Correspondance)
∴ Seg AC ≅ Seg CB ____________ c.s.c.t.
Hence Proved
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