Solve it please I really need it and don't write out of track answers.
6a²-13a+5
Answers
Answer:
Step by Step Solution:
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Reformatting the input :
Changes made to your input should not affect the solution:
(1): "a2" was replaced by "a^2".
STEP
1
:
Equation at the end of step 1
((2•3a2) - 13a) + 6
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring 6a2-13a+6
The first term is, 6a2 its coefficient is 6 .
The middle term is, -13a its coefficient is -13 .
The last term, "the constant", is +6
Step-1 : Multiply the coefficient of the first term by the constant 6 • 6 = 36
Step-2 : Find two factors of 36 whose sum equals the coefficient of the middle term, which is -13 .
-36 + -1 = -37
-18 + -2 = -20
-12 + -3 = -15
-9 + -4 = -13 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and -4
6a2 - 9a - 4a - 6
Step-4 : Add up the first 2 terms, pulling out like factors :
3a • (2a-3)
Add up the last 2 terms, pulling out common factors :
2 • (2a-3)
Step-5 : Add up the four terms of step 4 :
(3a-2) • (2a-3)
Which is the desired factorization
Final result :
(2a - 3) • (3a - 2)
Step-by-step explanation:
Answer:
a=1/2 or a=5/3
Step-by-step explanation:
6a²-13a+5=0
by spiliting the middle term
6a²-10a-3a+5
2a(3a-5)-1(3a-5)
(2a-1)(3a-5)
hence a=1/2 or a=5/3
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