Solve it please....its really urgent
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In the given figure;
AD is perpendicularto EF
➡∠EAD=∠FAD=90°
Given:
∠EAB=∠FAC
➡∠EAD-∠EAB=∠FAD-∠FAC
➡∠BAD=∠CAD
In △ACD, ∠BAD=∠CAD [Proved above]
∠ADB=∠ADC=90°[Given AD ⊥ BC]
and AD=AD
△ABD≅△ACD [By ASA]
Hence proved.
△ABD≅△ACD➡AB=AC and BD=CD [By C.P.C.T.C.]
➡2x+3=3y+1 and x=y+1
➡2x-3y= -2 and x-y=1
On solving we get;
x=5 and y=4
Hope it helps you....
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