Question

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Answer 1

answer : 867°C

at the room temperature 27°C , the resistance of the heating element is R_${27^{\circ}}= \frac{230}{3.2}=71.875\OmegaR$

27 = 3.2230

=71.875Ω

[ according to Ohm's law, V = IR , so , R = V/I ]

at the steady temperature t°C , the resistance , $R_t=\frac{230}{2.8}= 82.143\OmegaR$]

t

= 2.8230 =82.143Ω

now, use the relation, $R=R_0[1+\alpha(T-T_0)]R=R$

0

[1+α(T−T

0

)]

here, R=R_t = 82.143$\OmegaR=R$

t

=82.143Ω

R_0=R_${27^{\circ}}=71.875\OmegaR$

0

=R

27

∘

=71.875Ω

$\alpha=1.7\times10^{-4}/^{\circ}Cα=1.7×10$

−4

/

∘

C

now, 82.143 = 71.875 [1 + 1.7 × 10^-4(t - 27)]

⇒82.143 - 71.875 = 71.875 × 1.7 × 10^-4(t - 27)

⇒ 0.084 × 10^4 = t - 27

⇒ 840 + 27 = t

⇒ t = 867°C

hence, temperature = 867°C

Answer 2

Answer:

Output:

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