solve it please please please
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Step-by-step explanation:answer is 90° as-
Angle BPQ + angle DQP =180° (co interor angles)
Multiply it by 1/2,
1/2 angle BPQ +1/2 angle DQP = 1/2(180)
Angle TPQ + angle TQP = 90 ......eq(1)(as PT and QT are bisectors)
Apply angle sum property to triangle PTQ,
Angle PTQ+angle TPQ +angle TQP=180.
Therefore, angle PTQ=90 (from eqn 1)
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