Question

Solve it please
please who have a right answer I mark him or her brainliest​

Answer 1

${ax}^{2} + bx + c \\ f(x) = k(x - \alpha )(x - \beta ) \\ i.e. \: \: {ax}^{2} + bx + c = k \: ( {x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ or \: {ax}^{2} + bx + c = {kx}^{2} - k( \alpha + \beta )x + ka \beta \\ equating \: the \: powers \: on \: both \: sides \: we \: get \: k = a \: - k( \alpha + \beta ) \: = b \: and \: k(a \beta ) = c \\ \alpha + \beta = - \frac{b}{a} and \: \alpha \beta = \frac{c}{a} \\ ..for \: polynomial = \: sum \: of \: zeroes \: = \frac{ - b}{a} \\ and \: product \: = \frac{c}{a \\ }$

Answer 2

please mark upper as a brainlist ❤️