solve it please quickly
Attachments:
Answers
Answered by
0
THE ANSWER IS B MAY BE NOT
Answered by
0
let us take x instead of theta..
(sinx - 2 sin^3 x)/(2cos^3x -cos x)
[sin x(1 - 2 sin^2 x)]/[cos x (2cos^2 x - 1 )]
sin x / cos x [ (1- 2(1- cos^2 x)/(2 cos^2 x -1)]
Tan x[(1-2+2 cos^ x)/(2 cos^2-1)]
Tan x [(2 cos^ x -1)/(2cos^ x -1)]
= tan x
(sinx - 2 sin^3 x)/(2cos^3x -cos x)
[sin x(1 - 2 sin^2 x)]/[cos x (2cos^2 x - 1 )]
sin x / cos x [ (1- 2(1- cos^2 x)/(2 cos^2 x -1)]
Tan x[(1-2+2 cos^ x)/(2 cos^2-1)]
Tan x [(2 cos^ x -1)/(2cos^ x -1)]
= tan x
Similar questions