Question

solve it please teacher​

Answer 1

Answer:

Step-by-step explanation:

We Know That:

$a^3 + b^3 + c^3 - 3abc =(a+ b + c)(a^2 +b^2 + c^2 -ab-bc-ac)$

Hence, if

$a+ b + c =0$,

$a^3 + b^3 + c^3 = 3abc$.

given, $a+b+2c =0$

So, $a^3 +b^3 + (2c)^3= 3ab(2c)$

hence,$a^3 + b^3 + 8c^3 = 6abc$

HENCE PROVED

Answer 2

Answer:

Step-by-step explanation: